How d you solve $3( 4+ 2b ) - b = 27$ ?

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Answer 1 · 2018-03-20T16:29:01

see below

We have, $3(4+2b)-b=27$
Simplifying,we get,
$12+6b-b=27$
$5b=27-12$
$b=15//5$
Thus, $b=3$

How d you solve 3( 4+ 2b ) - b = 273( 4+ 2b ) - b = 27?