How I write this expression in terms of sines and/or cosines, and then simplify? 1+cosαtanαcscα/cscα

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Answer 1 · 2018-03-23T06:53:30

$1 + sin α$ $1+sin alpha$

$1 + cos α tan α \frac{csc α}{csc α}$ $1+cos alpha tan alpha csc alpha/csc alpha$

$1+(cos alpha × tan alpha × cancel(csc alpha))/ cancel(csc alpha)$

$1+ cos alpha × tan alpha color(blue)(rarr 1)$

$tan alpha= sin alpha/cos alpha color(blue)(rarr 2)$

Putting value of $tan alpha$ from $color(blue)(2)$ in $color(blue)(1)$

$1+ cos alpha × sin alpha/ cos alpha$

$1+ cancel(cos alpha) × sin alpha/ cancel(cos alpha)$

$1+ sin alpha$