How I write this expression in terms of sines and/or cosines, and then simplify? 1+cosαtanαcscα/cscα

1 Answer
Mar 23, 2018

1+sin alpha1+sinα

Explanation:

1+cos alpha tan alpha csc alpha/csc alpha1+cosαtanαcscαcscα

1+(cos alpha × tan alpha × cancel(csc alpha))/ cancel(csc alpha)

1+ cos alpha × tan alpha color(blue)(rarr 1)

tan alpha= sin alpha/cos alpha color(blue)(rarr 2)

Putting value of tan alpha from color(blue)(2) in color(blue)(1)

1+ cos alpha × sin alpha/ cos alpha

1+ cancel(cos alpha) × sin alpha/ cancel(cos alpha)

1+ sin alpha