How do you solve this equation by factoring?

Question

#(5i)/(3-5i)#

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Answer 1 · 2018-03-25T02:30:05

#(5i)/(3-5i)=5/34(3i-5)-=15/34i-25/34#

#(5i(3+5i))/(3^2-25i^2)#

#2#. Simplify

#(15i-25)/(9+25)=>(5(3i-5))/34=>5/34(3i-5)#