How do you solve this equation by factoring?

Question

$\frac{5 i}{3 - 5 i}$ $(5i)/(3-5i)$

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Answer 1 · 2018-03-25T02:30:05

$\frac{5 i}{3 - 5 i} = \frac{5}{34} (3 i - 5) \equiv \frac{15}{34} i - \frac{25}{34}$ $(5i)/(3-5i)=5/34(3i-5)-=15/34i-25/34$

$\frac{5 i (3 + 5 i)}{3^{2} - 25 i^{2}}$ $(5i(3+5i))/(3^2-25i^2)$

$2$ $2$ . Simplify

$\frac{15 i - 25}{9 + 25} \Rightarrow \frac{5 (3 i - 5)}{34} \Rightarrow \frac{5}{34} (3 i - 5)$ $(15i-25)/(9+25)=>(5(3i-5))/34=>5/34(3i-5)$