How do you solve 4(v+6)-2(-3+5v)= -6v-134(v+6)−2(−3+5v)=−6v−13?

1 Answer
ste b.
Mar 25, 2018

So, based off looking, I will just expand and see what happens.

4(v+6)-2(-3+5v)=-6v-134(v+6)−2(−3+5v)=−6v−13
4v+24+6-10v+6v=-134v+24+6−10v+6v=−13
10v-10v=-4310v−10v=−43
v(10-10)=-43v(10−10)=−43
v=43/0v=430

So, v is undefined but it is approaching infinity (when I have a very small denominator in a fraction, the value will approach infinity).

Related questions
Impact of this question
1367 views around the world
You can reuse this answer
Creative Commons License