How do you solve 4(v+6)−2(−3+5v)=−6v−13?

1 Answer
ste b.
Mar 25, 2018

So, based off looking, I will just expand and see what happens.

4(v+6)−2(−3+5v)=−6v−13
4v+24+6−10v+6v=−13
10v−10v=−43
v(10−10)=−43
v=430

So, v is undefined but it is approaching infinity (when I have a very small denominator in a fraction, the value will approach infinity).

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