Question

How do you solve `4(v+6)-2(-3+5v)= -6v-13`?

Answer 1

So, based off looking, I will just expand and see what happens.

`4(v+6)-2(-3+5v)=-6v-13`
`4v+24+6-10v+6v=-13`
`10v-10v=-43`
`v(10-10)=-43`
`v=43/0`

So, v is undefined but it is approaching infinity (when I have a very small denominator in a fraction, the value will approach infinity).