above equation could be like this #{3(x-3)-2(x+5)}/{(x+5)(x-3)}# and this is equal to #(x-19)/(x^2+2x-15)#
so the answer is #(x-19)/(x^2+2x-15)# if you want to know x about #(x-19)/(x^2+2x-15)=0# the x could 19 but not -5 or 3 because denominator can't be zero