How do you solve for \frac { h - 2} { h - 3} = \frac { 1} { - c } for h?

1 Answer
Mar 28, 2018

h=(2c+3)/(c+1)

Explanation:

Given:
(h-2)/(h-3)=1/(-c)

Cross multiplying

(h-2)(-c)=(h-3))1)

-ch+2c=h-3

2c+3=h+ch

2c+3=(1+c)h

h=(2c+3)/(c+1)