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How do you factor the expression $16 x^{2} - 52 x - 48$ $16x^2 - 52x - 48$ ?

1 Answer

Mar 28, 2018

$4 (x - 4) (4 x + 3)$ $4(x - 4) (4x + 3)$

Explanation:

$16 x^{2} - 52 x - 48$ $16x^2 - 52x - 48$

Factorising means putting into brackets
Factor out the common term which is 4
$4 (4 x^{2} - 13 x - 12)$ $4(4x^2 - 13x - 12)$
Now factor what is inside the brackets
$(x - 4) (4 x + 3)$ $(x - 4) (4x + 3)$
Add the common term back in front of the bracket
$4 (x - 4) (4 x + 3)$ $4(x - 4) (4x + 3)$

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