What is the standard form of y= (-x+1)^3-(-3x+1)^2? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Shiva Prakash M V Mar 29, 2018 y=-28x^3+30x^2-12x+2 Explanation: y=(-x+1)^3-(-3x+1)^2 y=(1-x)^3+(1-3x)^2 y=1^3-3xx1^2 xxx+3xx1xxx^2-x^3+1^3-3xx1^2xx3x+3xx1xx(3x)^2-(3x)^3 y=1-3x+3x^2-x^3+1-9x+27x^2-27x^3 y=-x^3-27x^3+3x^2+27x^2-9x-3x+1+1 y=-28x^3+30x^2-12x+2 Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is x^2+3x^{\frac{1}{2}} a polynomial? How do you express -16+5f^8-7f^3 in standard form? What is the degree of 16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2? What is the degree of the polynomial x^4-3x^3y^2+8x-12? What is the difference between a monomial, binomial and polynomial? How do you write y = 2/3x + 5 in standard form? See all questions in Polynomials in Standard Form Impact of this question 1908 views around the world You can reuse this answer Creative Commons License