What is the standard form of y= (-x+1)^3-(-3x+1)^2?

1 Answer
Shiva Prakash M V
Mar 29, 2018

y=-28x^3+30x^2-12x+2

Explanation:

y=(-x+1)^3-(-3x+1)^2

y=(1-x)^3+(1-3x)^2

y=1^3-3xx1^2 xxx+3xx1xxx^2-x^3+1^3-3xx1^2xx3x+3xx1xx(3x)^2-(3x)^3

y=1-3x+3x^2-x^3+1-9x+27x^2-27x^3

y=-x^3-27x^3+3x^2+27x^2-9x-3x+1+1

y=-28x^3+30x^2-12x+2

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