How do you evaluate [32−(12−34)2]−1+[(3+13)2−(3−13)2]−12?

1 Answer
AltairSafir
Mar 29, 2018

[32−(2−34)2]−1+[(9+13)2−(9−13)2]−12

Explanation:

=[32−(−14)2]−1+[(103)2−(83)2]−12=
=[32−18]−1+[1009−649]−12=
=[12−18]−1+[100−649]−12=
=[118]−1+[369]−12=
=1811+1[369]12=
=118+[936]12=
=118+[3262]12=
=118+36=118+12=11+48=158

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