How do you solve by substitution $11 y - 3 x = 18$ $11y-3x=18$ and $- 3 = - 16 y + 33$ $-3=-16y+33$ ?

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How do you solve by substitution $11 y - 3 x = 18$ $11y-3x=18$ and $- 3 = - 16 y + 33$ $-3=-16y+33$ ?

1 Answer

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Answer 1 · 2018-03-29T18:04:25

From the second equation calculate y and put it in the second equation.

Explanation:

$- 3 = - 16 y + 33$ $-3=-16y+33$
$16 y = 36$ $16y=36$
$y = \frac{9}{4}$ $y=9/4$

$11 y - 3 x = 18$ $11y-3x=18$
$11 \cdot (\frac{9}{4}) - 3 x = 18$ $11*(9/4)-3x=18$
$- 3 x = 18 - \frac{99}{4} = - \frac{27}{4}$ $-3x=18-99/4=-27/4$
$x = \frac{9}{4}$ $x=9/4$

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How do you solve by substitution $11 y - 3 x = 18$ $11y-3x=18$ and $- 3 = - 16 y + 33$ $-3=-16y+33$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you solve by substitution 11y−3x=1811y-3x=18 and −3=−16y+33-3=-16y+33?

1 Answer

Explanation:

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How do you solve by substitution $11 y - 3 x = 18$ $11y-3x=18$ and $- 3 = - 16 y + 33$ $-3=-16y+33$ ?