How do you solve $\frac { 1} { 2} x + 5\leq 8$ ?

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Answer 1 · 2018-03-30T19:08:08

$1/2x+5<=8$

$rArrx<=6$

The algebraic rules for solving inequalities are almost exactly the same as for solving equations.

$1/2x+5<=8$

$rArr1/2x+cancel5-cancelcolor(red)5<=8-color(red)(5)$

$rArr1/2x<=3$

$rArrcancelcolor(red)2*1/cancel2x<=color(red)2*3$

$rArrx<=6$

How do you solve \frac { 1} { 2} x + 5\leq 8\frac { 1} { 2} x + 5\leq 8?