How do you solve the system of equations -x - 8y = - 16 and 6x + 4y = 8?

1 Answer
Mar 31, 2018

(x,y)-=(0,2)

Explanation:

-x-8y=-16

6x+4y=8

If
a_(11)x+a_(12)y=b_(11)

a_(21)x+a_(22)y=b_(22)

Cramer's rule can be applied

(x,y)=((b_(11)a_(22)-b_(22)a_(12))/(a_(11)a_(22)-a_(21)a_(12)),(a_(11)b_(22)-a_(22)b_(12))/(a_(11)a_(22)-a_(21)a_(12)))

Thus, comparing

x=((-16xx4-8xx(-8)))/((-1xx4-6xx-8))= ((-64+64))/((-4+48))=0/44=0

y=((-1xx8-6xx(-16)))/((-1xx4-6xx-8))=((-8+96))/((-4+48))=88/44=2

(x,y)-=(0,2)