How do you add $2 \sqrt{18} + 11 \sqrt{2}$ $2\sqrt { 18} + 11\sqrt { 2}$ ?

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How do you add $2 \sqrt{18} + 11 \sqrt{2}$ $2\sqrt { 18} + 11\sqrt { 2}$ ?

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Answer 1 · 2018-04-02T10:16:00

$2 \sqrt{18} + 11 \sqrt{2} = 17 \sqrt{2}$ $2sqrt18+11sqrt2=17sqrt2$

Explanation:

We can rewrite $\sqrt{18}$ $sqrt18$ as follows:
$2 \sqrt{18} + 11 \sqrt{2} = 2 \sqrt{2 \cdot 9} + 11 \sqrt{2} = 2 \sqrt{2} \sqrt{9} + 11 \sqrt{2} =$ $2sqrt18+11sqrt2=2sqrt(2*9)+11sqrt2=2sqrt2sqrt9+11sqrt2=$

$= 6 \sqrt{2} + 11 \sqrt{2}$ $=6sqrt2+11sqrt2$

Now we can factor out $\sqrt{2}$ $sqrt2$ , giving us the answer:
$= \sqrt{2} (6 + 11) = \sqrt{2} \cdot 17 = 17 \sqrt{2}$ $=sqrt2(6+11)=sqrt2*17=17sqrt2$

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How do you add $2 \sqrt{18} + 11 \sqrt{2}$ $2\sqrt { 18} + 11\sqrt { 2}$ ?

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