How many grams of calcium nitrate are needed to make 3.30L of a 0.10 M solution?

Question

How many grams of calcium nitrate are needed to make 3.30L of a 0.10 M solution?

1 Answer

Impact of this question

3142 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-03T23:52:15

See below

Explanation:

We'll use $Molarity = \frac{moles}{liter}$ $"Molarity" = ("moles")/("liter")$ , and rearrange to get $moles = Molarity \times Liters$ $"moles" = "Molarity" xx "Liters"$

$0.1 M \times 3.30 L = 0.33 moles$ $0.1M xx 3.30L = 0.33 "moles"$

Molar mass of Calcium Nitrate is 164.1g/mol

$0.33 moles \times 164.1 \frac{g}{mol}$ $0.33 "moles" xx 164.1g/"mol"$ = 54.15 g $C a {(N O_{3})}_{2}$ $Ca(NO_3)_2$

Science

Math

Humanities

... and beyond

How many grams of calcium nitrate are needed to make 3.30L of a 0.10 M solution?

1 Answer

Explanation:

Related questions

Impact of this question