How many grams of calcium nitrate are needed to make 3.30L of a 0.10 M solution?

1 Answer
Dave
Apr 3, 2018

See below

Explanation:

We'll use #"Molarity" = ("moles")/("liter")#, and rearrange to get #"moles" = "Molarity" xx "Liters"#

#0.1M xx 3.30L = 0.33 "moles"#

Molar mass of Calcium Nitrate is 164.1g/mol

#0.33 "moles" xx 164.1g/"mol"# = 54.15 g #Ca(NO_3)_2#

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