Question

How do you subtract `16- 8\frac { 1} { 3}`?

Answer 1

Your answer for that equation equals `7 2/3`

Explanation:

Well you put 16 as an improper fraction. So it would be `16/1` and then you would turn `8 1/3` into an improper fraction which would equal `25/3` . After that you would get a common denominator which in this case is 3. You would multiply the 16 by 3 to make it even. `25/3-48/3=-23/3`. Now that is an improper fraction so you do this `23/3=7 2/3`

Answer 2

Turn both numbers into improper fractions.

Explanation:

To turn `16` into an improper fraction you have to:

1. Times `16` by `3`
2. Put that number over `3`

That gives you `48/3`

To double-check your answer, you can divide `48` by `3`. It should equal `16`.

To turn `8 1/3` into an improper fraction you have to:

1. Times `8` by the `3` in the denominator
2. Add the `1` from the numerator
3. Put that number over `3`

That gives you `25/3`

To double-check your answer, you can divide `25` by `3`. It should equal `8 1/3`.

To find the difference between the two numbers simply subtract them from each other. This will look like:

`48/3-25/3`

Subtract the numerators from each other, but keep the denominators the same. Your answer should be:

`23/3` which simplifies to `7 2/3`