What is/are the maximum number of possible real roots of the equation? a) 3 b) 4 c) 5 d) 0

Question

#x^5 - 6x^2 - 4x + 5 = 0#

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Answer 1 · 2018-04-05T08:27:38

See below.

None of the answers is satisfactory

Comparing the plots for

#y = x^5# and
#y = -6x^2-4x+5#

the conclusion is that there is only a real root.

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