How much force is needed to accelerate a $4.0$ $4.0$ $k g$ $kg$ physics book to an acceleration of $2.0$ $2.0$ $m$ $m$ $/$ $/$ $s^{2}$ $s^2$ ?

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How much force is needed to accelerate a $4.0$ $4.0$ $k g$ $kg$ physics book to an acceleration of $2.0$ $2.0$ $m$ $m$ $/$ $/$ $s^{2}$ $s^2$ ?

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Answer 1 · 2018-04-05T20:50:37

Force $=$ $=$ $8.0 k g m / s^{2}$ $8.0kgm//s^2$

Explanation:

Force $=$ $=$ mass x acceleration
Mass $=$ $=$ $4.0 k g$ $4.0kg$
Acceleration $=$ $=$ $2.0 m / s^{2}$ $2.0m//s^2$
Hence,force $=$ $=$ ( $4.0$ $4.0$ x $2.0$ $2.0$ ) $k g m / s^{2}$ $kgm//s^2$
$=$ $=$ $8.0 k g m / s^{2}$ $8.0kgm//s^2$

Answer 2 · 2018-04-06T00:29:58

$8$ $8$ newtons

Explanation:

We use Newton's second law of motion, which states that,

$F = m a$ $F=ma$

$m$ $m$ is the mass of the object in kilograms

$a$ $a$ is the acceleration of the object in meters per second

And so, plugging in the values, we get,

$F=4 \ "kg"*2 \ "m/s"^2$

$=8 \ "N"$

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How much force is needed to accelerate a $4.0$ $4.0$ $k g$ $kg$ physics book to an acceleration of $2.0$ $2.0$ $m$ $m$ $/$ $/$ $s^{2}$ $s^2$ ?

2 Answers

Explanation:

Explanation:

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How much force is needed to accelerate a $4.0$ $4.0$ $k g$ $kg$ physics book to an acceleration of $2.0$ $2.0$ $m$ $m$ $/$ $/$ $s^{2}$ $s^2$ ?