Question

The point (2k-8,10)lies on the Y axis.find the value of k?

Answer 1

k = 4

Explanation:

This problem gives you some extraneous (extra) information in an attempt to trick you.

If the point lies on the y-axis then the `x` value of the point must be zero. Consider that any point on the y-axis has the form (0, `n`), where `n` is some number.

Since our point can be written as `(0, n)`, it follows that `(0, n) = (2k-8, 10)`. So `0 = 2k-8` and `n = 10`. We are only interested in the value of `k`. The algebra, at this point, is:

`0 = 2k - 8`
`8 = 2k`
`4 = k`

And we have our answer: `k = 4`.

Answer 2

`k=4`

Explanation:

The point `(2k-8,10)` can only lie on the `y`-axis when the `x` coordinate is `0`.

Therefore, `2k-8=0 => k=4`