Question

What is the mass percent of sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water?

Answer 1

`mass %=29.7%`

Explanation:

moles of sodium fluoride = `(W(given mass))/(M(molar mass))`
`0.64=W/42`
`W=26.88` gm
`mass %=[mass_(solute)]/[mass_(solution)]*100=26.88/90.48*100=29.7%`