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Sin(x+y)= 1, cos (x-y)= $\sqrt{(\frac{3}{2})}$ $sqrt((3/"2")$ find value of x and y?

$\sqrt{(\frac{3}{2})}$ $sqrt((3/"2")$

1 Answer

Apr 8, 2018

See below.

Explanation:

No real values for solution because $cos (x - y) > 1$ $cos(x-y) > 1$

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