How do you solve 2/5=(y-26)/(y+11)25=y26y+11?

3 Answers
Apr 8, 2018

152/31523

Explanation:

First, multiply both sides by 5(y+11)5(y+11) to get rid of all denominators.

2/cancel5 times cancel5(y+11)=(y-26)/cancel((y+11)) times 5cancel((y+11))

Now simplify to get: 2(y+11)=5(y-26)

Now multiply both sides out. 2y+22=5y-130

Now place constants on the same side and the variables on the same side. 3y=152

Now, just divide both side by 3 and you get your answer.

y=152/3

Now, 152 does not evenly divide by three, so we can present it as an improper fraction (152/3) or a mixed fraction (50 2/3).

Apr 8, 2018

y = 50 2/3 ~~50.7

Explanation:

2/5 = (y - 26)/(y + 11)

First, cross multiply;

2(y + 11) = 5(y - 26)

Secondly, eliminate the brackets;

2y + 22 = 5y - 130

Thirdly, collect like terms;

2y - 5y = - 130 - 22

-3y = - 152

Divide both sides by -3

(-3y)/(-3) = (-152)/(-3)

(cancel(-3)y)/cancel(-3) = (cancel-152)/(cancel-3)

y = 152/3

y = 50 2/3 ~~50.7

Apr 8, 2018

y=152/3

Explanation:

=2/5=(y-26)/(y+11)

=2y+22=5y-130

=5y-2y=130+22

=3y=152

=y=152/3

Hope it helps!