How do you factor $t^{2} - 5 t + 6$ $t^2-5t+6$ ?

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How do you factor $t^{2} - 5 t + 6$ $t^2-5t+6$ ?

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Answer 1 · 2018-04-08T18:53:26

$t^{2} - 5 t + 6 = (t - 2) (t - 3)$ $t^2 - 5t +6 = (t-2)(t-3)$

Explanation:

In a trinomial with the degree $2$ $2$ and with $1$ $1$ as the leading coefficient, you need to find two numbers that add up to the second term and have a product that is the third term.

In this trinomial, the sum (second term) is $- 5$ $-5$ and the product (third term) is $6$ $6$ .
The numbers $- 2$ $-2$ and $- 3$ $-3$ satisfy the terms.
Therefore, $t^{2} - 5 t + 6 = (t - 2) (t - 3)$ $t^2 - 5t +6 = (t-2)(t-3)$ .

Answer 2 · 2018-04-08T18:57:22

$(t - 2) (t - 3)$ $(t-2)(t-3)$

Explanation:

$the factors of + 6 which sum to - 5 are - 2 and - 3$ $"the factors of + 6 which sum to - 5 are - 2 and - 3"$

$\Rightarrow t^{2} - 5 t + 6 = (t - 2) (t - 3)$ $rArrt^2-5t+6=(t-2)(t-3)$

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How do you factor $t^{2} - 5 t + 6$ $t^2-5t+6$ ?

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