Make D the subject of ?

Question

Z=BD^2/6

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Answer 1 · 2018-04-09T14:04:37

D= $sqrt6Z/B$

The first thing you do is multiplying both sides by 6

on the other side, it will be multiplied by Z
this gives 6Z=B $D^2$

to remove the power of 2 from D you square root the other side
$sqrt6Z$ = BD

then divide both sides by B to get D by itself
$sqrt6Z/B$