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How do you solve $\frac{2}{3 b - 2} = 4$ $2/(3b-2) = 4$ ?

1 Answer

Apr 9, 2018

$\frac{2}{3 b - 2}$ $2/ (3b-2)$ = 4

move denominator to other side by multiplying
$2 = 4 (3 b - 2)$ $2 = 4(3b-2)$
Expand brackets
$2 = 12 b - 8$ $2= 12b-8$
add 8 to both sides
$2 + 8 = 12 b$ $2+8=12b$
$10 = 12 b$ $10=12b$
Divide both sides by 12
$\frac{10}{12} = b$ $10/12 = b$

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