Question

How do you solve `1+x/(2-x)=(6x)/(2-x)` and check for extraneous solutions?

Answer 1

`x=1/3`

Explanation:

Multiply everything by `(2-x)` to get rid of the fractions

`1(2-x)+x=6x`

`=>` `2-x+x=6x`

`=>` `2=6x`

`x=2/6`

`x=1/3`