Simplify each of the following using the trig identities. #(sin^2x)+(sin^2x)(tan^2x)#?

1 Answer
Apr 11, 2018

#sin^2x+sin^2xtan^2x=tan^2x#

Explanation:

Simplify: #sin^2x+sin^2xtan^2x#

First, factor out #sin^2x# from the expression:

#sin^2x(1+tan^2x)#

Now we can use this trig identity

#1+tan^2x=sec^2x#

Now we have

#sin^2xsec^2x#

We know that

#secx=1/cosx#

So it is then true that

#sec^2x=1/cos^2x#

Now we have

#sin^2x/cos^2x#

We know that

#tanx=sinx/cosx#

So it is then true that

#tan^2x=sin^2x/cos^2x#

So for the final answer we have is

#tan^2x#