What is $\sqrt{{(- 9)}^{2}}$ $sqrt((-9)^2)$ ?

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Answer 1 · 2018-04-11T01:44:37

The result is $9$ $9$ .

To simplify squares inside radicals, take the absolute value of what is being squared, like this:

$\sqrt{x^{2}} = | x |$ $sqrt(x^2)=|x|$

This is because a square root cannot equal a negative number. Here's is your expression:

$= \sqrt{{(- 9)}^{2}}$ $color(white)=sqrt((-9)^2)$

$= | - 9 |$ $=|-9|$

$= 9$ $=9$

That's the result. You can check using a calculator:

![https://www.desmos.com/calculator]( useruploads.socratic.org )

Hope this helped!

Answer 2 · 2018-04-11T01:46:51

$\pm 9$ $+-9$

$\sqrt{{(- 9)}^{2}}$ $sqrt((-9)^2)$
$= \sqrt{81}$ $=sqrt81$
$= \pm 9$ $=+-9$

What is sqrt((-9)^2)√(−9)2sqrt((-9)^2)?