How do you differentiate $f(x)=cot(e^sqrt(x^2-1))$ using the chain rule?

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Answer 1 · 2018-04-12T05:09:37

$d/dx f(x)=-csc^2(e^sqrt(x^2-1))(e^sqrt(x^2-1))(1/2(x^2-1)^-(1/2))(2x)$

$d/dxcot(x)=-csc^2(x)$
$d/dxe^x=e^x$
$d/dxx^n=nx^(n-1)$

$f(x)=cot(e^sqrt(x^2-1))$
$d/dx f(x)=-csc^2(e^sqrt(x^2-1))(e^sqrt(x^2-1))(1/2(x^2-1)^-(1/2))(2x)$

How do you differentiate f(x)=cot(e^sqrt(x^2-1)) f(x)=cot(e^sqrt(x^2-1)) using the chain rule?