How do you find the derivatives of $y=(5x-2)^3(6x+1)^2$ by logarithmic differentiation?

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Answer 1 · 2018-04-14T10:48:01

$y' = (5x-2)^3(6x+1)^2$ $((15)/(5x-2)+(12)/(6x+1))$

1/ ln(y) = $3ln(5x-2) + 2ln(6x+1)$
2/ $(1)/(y) y'$ = $(3)((1)/(5x-2))(5) + (2)((1)/(6x+1))(6)$

3/ $(1)/(y) y'$ = $(15)/(5x-2) + (12)/(6x+1)$

4/ y' = y $((15)/(5x-2) + (12)/(6x+1))$

5/ y' = $(5x-2)^3(6x+1)^2$ $((15)/(5x-2) + (12)/(6x+1))$

How do you find the derivatives of y=(5x-2)^3(6x+1)^2y=(5x-2)^3(6x+1)^2 by logarithmic differentiation?