Find the other dive trigonometric functions OF the acute angle A, given that sec A=2 ?

2 Answers
Nityananda
Apr 15, 2018

Given,secA = 2.
So, cosA = 1/2 = cos 60.
Then, A = 60 degree.
Now, Sin 60 = #(sqrt 3)/2#,tan 60 = #sqrt 3#, csc 60 = #2/(sqrt3)#, cot 60 =#1/(sqrt3)#.

ANOTHER WAY
We know, secA =#2/1= (hypotenuse)/(base)#
So, height = #sqrt[(hypotenuse)^2-(base)^2]#
So, height = #sqrt[2^2-1^2]#
#rArr sqrt3#

Nityananda
Apr 15, 2018

Given,secA = 2.
So, cosA = 1/2 = cos 60.
Then, A = 60 degree.
Now, Sin 60 = #(sqrt 3)/2#,tan 60 = #sqrt 3#, csc 60 = #2/(sqrt3)#, cot 60 =#1/(sqrt3)#.

ANOTHER WAY
We know, secA =#2/1= (hypotenuse)/(base)#
So, height = #sqrt[(hypotenuse)^2-(base)^2]#
So, height = #sqrt[2^2-1^2]#
#rArr sqrt3#
Now sinA =#(height)/(hypotenuse)=sqrt3/2#
CosA= #(base)/(hypotenuse)=1/2#,
TanA = #(height)/(base)=(sqrt3)/1#
CscA = 1/sinA =#1/[(sqrt3)/2]= 2/(sqrt3)#,
CotA= 1/tanA =#1/(sqrt3)#

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