How do you solve $a^ { 2} + 24^ { 2} = 26^ { 2}$ ?

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Answer 1 · 2018-04-15T13:37:06

$a=+-10$

$a^2+24^2=26^2$
$rArr a^2=26^2-24^2$
$rArr a^2=676-576$
$rArr a=sqrt100$
$rArr a=+-10$

Hope this helps :)

Answer 2 · 2018-04-15T15:59:02

$+-10$

$a^2+24^2=26^2$

=>a^2=26^2-24^2#

the $RHS$ is difference of squares

$a^2=(26-24)(26+24)$

$a^2=2xx50=100$

$a=+-sqrt100=+-10$

How do you solve a^ { 2} + 24^ { 2} = 26^ { 2}a^ { 2} + 24^ { 2} = 26^ { 2}?