How do you solve $\frac{1}{2} x + 2 = \frac{3}{5}$ $\frac { 1} { 2} x + 2= \frac { 3} { 5}$ ?

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Answer 1 · 2018-04-15T17:17:31

$x = - \frac{14}{5}$ $x=-14/5$

$\frac{1}{2} x + 2 = \frac{3}{5} / \cdot 10$ $1/2x+2=3/5 //*10$

$10 \cdot \frac{1}{2} x + 10 \cdot 2 = 10 \cdot \frac{3}{5}$ $10*1/2x+10*2=10*3/5$

$color(green)5color(red)cancel10*1/color(red)cancel2x+20=color(green)2color(red)cancel10*3/color(red)cancel5$

$5x+20=6$

$5x=6-20$

$5x=-14// -:5$

$(5x)/5=-14/5$

$(color(red)cancel5x)/color(red)cancel5=-14/5$

$x=-14/5$

How do you solve \frac { 1} { 2} x + 2= \frac { 3} { 5}12x+2=35\frac { 1} { 2} x + 2= \frac { 3} { 5}?