How do you solve the equations #8x + 3y = 16# and #2x + y = 4#?

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Answer 1 · 2018-04-16T18:44:03

#x=2#, #y=0#

There are different methods to solve these equations.

Solving using the Elimination method

Consider the given equations:

#8x+3y=16# . . . . . (1)
#2x+y=4# . . . . . (2)

In order to make the coefficients of the variable 'y' the same, multiply equation (2) with 3.

Then,
#6x+3y=12# . . . . . (3)

Now, in order to eliminate the variable 'y', subtract (3) from (1).

Then we get,
#2x+0y=4#

That is,
#2x=4#
#x=4/2#
#x=2#

Now, substitute this value in (2).

Then,
#2(2)+y=4#
#4+y=4#
#y=4-4#
#y=0#