How do you solve $\frac { 4} { x - 1} = \frac { 8} { x + 2}$ ?

Question

1221 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-17T02:54:31

$x=4$

See below.

$color(white)(@@@@@@@@@@@@@@@@@)$
Cross multiply.

$4/(x -1)=8/(x+2)$

You get,

$4(x+2)=8(x-1)$

Now, multiply the terms.

$4x+8=8x-8$

Bring the $8x$ to $color(red)(LHS)$ and $8$ to $color(red)(RHS)$ .

$4x -8x=-8-8$

(Sign changes when the terms are brought to opposite side)

$-4x=-16$

Divide both sides by $-4$ .

$x=4$

Hope this helps :)

How do you solve \frac { 4} { x - 1} = \frac { 8} { x + 2}\frac { 4} { x - 1} = \frac { 8} { x + 2}?