What is the value of xx in the equation (3/4)x + 2 = (5/4)x - 6(34)x+2=(54)x−6 ?

3 Answers
Lucy
Apr 17, 2018

x=16x=16

Explanation:

(3/4)x+2=(5/4)x-6(34)x+2=(54)x−6

2+6=(5/4)x-(3/4)x2+6=(54)x−(34)x

8=1/2x8=12x

x=16x=16

James M.
Apr 17, 2018

x = 16x=16

Explanation:

Re-arrange the equation.

Add 66 to both sides:

(3/4)x + 2 + 6 = (5/4)x - 6 + 6(34)x+2+6=(54)x−6+6
(3/4)x + 8 = (5/4)x(34)x+8=(54)x

Multiply out (3/4)x " and " (5/4)x(34)x and (54)x:

(3x)/43x4 and (5x)/45x4

Multiply it all by 4:

3x + 8(4) = 5x3x+8(4)=5x

Solve:

3x - 3x + 32 = 5x - 3x3x−3x+32=5x−3x
32 = 2x32=2x

x = 16x=16

Jim G.
Apr 17, 2018

x=16x=16

Explanation:

"collect terms in x on one side of the equation and"collect terms in x on one side of the equation and
"numeric values on the other side"numeric values on the other side

"subtract "3/4x" from both sides"subtract 34x from both sides

cancel(3/4x)cancel(-3/4x)+2=5/4x-3/4x-6

rArr2=1/2x-6

"add 6 to both sides"

2+6=1/2xcancel(-6)cancel(+6)

rArr8=1/2x

"multiply both sides by 2"

rArrx=16" is the solution"

Related questions
Impact of this question
2636 views around the world
You can reuse this answer
Creative Commons License