Three consecutive multiples of 4 whose sum is 52?

1 Answer
Apr 18, 2018

This problem has no solutions, at least as written. See below for explanation.

Explanation:

Let the smallest of these three numbers be labeled #x#.

Because we are looking for consecutive multiples of 4, each of the larger numbers will be 4 larger than the one before it. The larger numbers can be labeled #x+4# and #x+8#, respectively.

These three numbers add up to 52.

#x+(x+4)+(x+8)=52#

Because we're simply adding all of the terms, the parentheses don't really matter. We can remove them.

#x+x+4+x+8=52#

We can combine like terms to make this problem a bit easier to solve.

When you combine like terms, you add up all of the terms in your expression that are "alike". In the case of this problem, we add the #x# terms together and add the plain numbers together as well.

#x+x+4+x+8=3x+12#

#3x+12=52#

#3x=40#

Unfortunately, because 40 divided by 3 does not give us a whole number, #x#, or our smallest number, will not be a multiple of 4. This problem therefore has no solutions as written.

If instead you meant that each of the numbers is simply four larger than the one before it, then we can continue.

#x=40/3#.

Add 4 to this number to get the second number, then 4 again for the third.

#40/3+4=52/3.#

#52/3+4=64/3.#

Therefore, the only set of numbers that somewhat satisfies the requirements laid out is #40/3#, #52/3#, #64/3#.