How do you graph $- 4 y = 3 x + 12$ $-4y=3x +12$ ?

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Answer 1 · 2018-04-19T13:22:54

y intercept = $- 3$ $-3$
x intercept = $- 4$ $-4$
gradient = $- \frac{3}{4}$ $-3/4$

First make it so that the equation equates to just y:

$y = - \frac{3 x}{4} - 3$ $y = -(3x)/4 -3$

y-intercept is -3 as when $x = 0, y = - 3$ $x = 0,y = -3$

x-intercept is:

$0 = - \frac{3 x}{4} - 3$ $0 = -(3x)/4 - 3$
$\frac{3 x}{4} = - 3$ $(3x)/4 = -3$
$3 x = - 12$ $3x = -12$

$x = - 4$ $x = -4$ graph{y = -(3x)/4 -3 [-10, 10, -5, 5]}

How do you graph −4y=3x+12-4y=3x +12?