How do you evaluate $(9 n^{2} - 4) (90 n^{3})$ $(9n ^ { 2} - 4) ( 90n ^ { 3} )$ ?

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Answer 1 · 2018-04-21T09:10:46

$81 n^{5} - 360 n^{3}$ $81n^5-360n^3$

$(9 n^{2} - 4) (90 n^{3}) = (9 n^{2}) .90 n^{3} - 4 . (90 n^{3})$ $(9n^2-4)(90n^3)=(9n^2).90n^3-4.(90n^3)$

$= 810 n^{5} - 360 n^{3}$ $=810n^5-360n^3$

How do you evaluate (9n ^ { 2} - 4) ( 90n ^ { 3} )(9n2−4)(90n3)(9n ^ { 2} - 4) ( 90n ^ { 3} )?