How do you solve the following system?: 2x +3y =5 , 8x +5y = -42x+3y=5,8x+5y=4

1 Answer
Apr 21, 2018

X = 33/16 and Y = 48/14X=3316andY=4814

Explanation:

Given:
2x+3y = 5 and 8x + 5y = -42x+3y=5and8x+5y=4
We need to make either one of the terms given, have similar coefficients to cancel out.

(2x + 3y = 5)(2x+3y=5) x 88
color(red)(16x + 24y = 40)16x+24y=40

(8x+ 5y = -4)(8x+5y=4) x 22
color(red)(16x + 10y = -8)16x+10y=8

Subtracting one from the other, we get:
16x + 24 y = 4016x+24y=40
-(16x+10y = -8)(16x+10y=8)

We get 14y = 48; y =48/1414y=48;y=4814

Substituting y = 48/144814 in any one of the equations.
2x + cancel(3)(14/cancel(48)) = 5
2x + 7/8 = 5
2x = 5-7/8
2x = (40-7)/8
:. x = 33/16