How do you solve #3x ^ { 2} = 2( x - 1)#?

1 Answer
Xodiac M.
Apr 22, 2018

#x1 = ((2+sqrt(-20))/6) and x2 =((2-sqrt(-20))/6)) #

Explanation:

Given:
#3x^2 = 2(x-1)#
#3x^2 = 2x - 2#

Rearranging this gives us a Quadratic Equation, that is;
#3x^2 -2x + 2 = 0#
#x = (-b+-sqrt(b^4-4ac))/(2a)#
# x1 = (-(-2)+sqrt((-2)^2-4(3)(2)))/(2*3)#
#x2 = (-(-2) -sqrt((-2)^2-4(3)(2)))/(2*3)#
Therefore, #x1 = color(red)((2+sqrt(-20))/6) and x2 = color(red)((2-sqrt(-20))/6)) #

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