Question

What is the force of friction between a block of ice that weighs 930 N and the ground if `mu` is 0.12?

Answer 1

`F_f=111.6N`

Explanation:

To find the force of friction, use the equation:

`F_f=muF_N`

You already know the weight of the object to be 930 N and the coefficient of friction is .12, so you can immediately solve to find the force of friction between the two surfaces.

`F_f=(.12)(930N)=111.6N`