The sum of two integer is 88.if greater is divided by smaller the quetioent is 5 and reminder is 10. Finf the integer?

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The sum of two integer is 88.if greater is divided by smaller the quetioent is 5 and reminder is 10. Finf the integer?

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Answer 1 · 2018-04-22T05:52:07

Smaller integer = 13, Greater integer = 75

Explanation:

Let x & y be the greater & smaller integers respectively:

$x + y = 88$ $x+y=88$ => eq-1
$\frac{x}{y} = 5 + \frac{10}{y}$ $x/y=5+10/y$ => eq-2
Solve for y in terms of x in eq-1:
$y = 88 - x$ $y=88-x$
Substitute for y in eq-2:
$\frac{x}{88 - x} = 5 + \frac{10}{88 - x}$ $x/(88-x)=5+10/(88-x)$
$x = 5 (88 - x) + 10$ $x = 5(88-x)+10$
$x + 5 x = 440 + 10$ $x+5x=440+10$
$6 x = 450$ $6x=450$
$x = 75$ $x=75$
$y = 88 - 75 = 13$ $y=88-75=13$
Check:
$75 + 13 = 88$ $75+13=88$
$\frac{75}{13} = 5 \frac{10}{13}$ $75/13=5 10/13$

Answer 2 · 2018-04-22T08:35:50

$75, 13$ $75,13$

Explanation:

Let $a and b$ $a and b$ be the two integers, and $a > b$ $a>b$ ,
$\Rightarrow a + b = 88, \Rightarrow a = 88 - b$ $=> a+b=88, => a=88-b$
given that if $\frac{a}{b}$ $a/b$ , then the quotient is 5 and the remainder is 10,
$\Rightarrow \frac{a - 10}{b} = 5$ $=> (a-10)/b=5$ ,
$\Rightarrow 88 - b - 10 = 5 b$ $=> 88-b-10=5b$ ,
$\Rightarrow 78 = 6 b$ $=> 78=6b$ ,
$\Rightarrow b = \frac{78}{6} = 13$ $=> b=78/6=13$
$\Rightarrow a = 88 - b = 88 - 13 = 75$ $=> a=88-b=88-13=75$

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The sum of two integer is 88.if greater is divided by smaller the quetioent is 5 and reminder is 10. Finf the integer?

2 Answers

Explanation:

Explanation:

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