How do you solve the following system?: 1/2x=y-1 , -x+3y=-7

1 Answer
Apr 24, 2018

x=-20

y=-9

Explanation:

The given equations are

1/2x = y-1
-x+3y = -7

From 1/2x = y-1

x=2(y-1)

Substituting this x value in equation -x+3y = -7

=> - (2(y-1) + 3y = -7

=> -2y +2 +3y = -7

=> y+2 = -7

=> y= -7-2

=> y = -9

Substitute this y value in any of the given equations to obtain the x value

-x +3y = -7

=> -x + 3(-9) = -7

=> -x -27 = -7

=> x = -20