How do you solve the following system?: $1/2x=y-1 , -x+3y=-7$

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Answer 1 · 2018-04-24T05:07:32

$x=-20$

$y=-9$

The given equations are

$1/2x = y-1$
$-x+3y = -7$

From $1/2x = y-1$

$x=2(y-1)$

Substituting this $x$ value in equation $-x+3y = -7$

$=> - (2(y-1) + 3y = -7$

$=> -2y +2 +3y = -7$

$=> y+2 = -7$

$=> y= -7-2$

$=> y = -9$

Substitute this $y$ value in any of the given equations to obtain the $x$ value

$-x +3y = -7$

$=> -x + 3(-9) = -7$

$=> -x -27 = -7$

$=> x = -20$

How do you solve the following system?: 1/2x=y-1 , -x+3y=-7 1/2x=y-1 , -x+3y=-7