How do you solve the following system?: 12x=y1,x+3y=7

1 Answer
Apr 24, 2018

x=20

y=9

Explanation:

The given equations are

12x=y1
x+3y=7

From 12x=y1

x=2(y1)

Substituting this x value in equation x+3y=7

(2(y1)+3y=7

2y+2+3y=7

y+2=7

y=72

y=9

Substitute this y value in any of the given equations to obtain the x value

x+3y=7

x+3(9)=7

x27=7

x=20