How do you solve $2 sin x - 1 = 0$ $2 sin x -1 = 0$ ?

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How do you solve $2 sin x - 1 = 0$ $2 sin x -1 = 0$ ?

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Answer 1 · 2018-04-24T05:32:08

There can be one Graphical approach to this question, see below :-

Explanation:

Since,

$2 sin x - 1 = 0$ $2sinx-1=0$

$\Rightarrow sin x = \frac{1}{2}$ $rArr sinx=1/2$

Now plot the graphs of $y_{1} = sin x$ $y_1=sinx$ and $y_{2} = \frac{1}{2}$ $y_2=1/2$ on same graph paper ; the point of intersections of both the graphs ( $i e .$ $ie.$ $y_{1} = y_{2}$ $y_1=y_2$ ) will be the solutions to the equation $2 sin x - 1 = 0$ $2sinx-1=0$ .

See the pic given below , the intersection points shown below are some of the infinite possible solutions to the given equation $2 sin x - 1 = 0$ $2sinx-1=0$ .

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How do you solve $2 sin x - 1 = 0$ $2 sin x -1 = 0$ ?

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