Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How to do this?

1 Answer

Apr 24, 2018

$θ = \frac{π}{3}, \frac{2 π}{3}$ $theta=pi/3,(2pi)/3$

Explanation:

We want to solve the equation

$2 sin (θ) - \sqrt{3} = 0$ $2sin(theta)-sqrt(3)=0$

Solve for $sin (θ)$ $sin(theta)$

$2 sin (θ) = \sqrt{3}$ $2sin(theta)=sqrt(3)$

$\Rightarrow sin (θ) = \frac{\sqrt{3}}{2}$ $=>sin(theta)=sqrt(3)/2$

And here the angles should be remembered as

$θ = \frac{π}{3}, \frac{2 π}{3}$ $theta=pi/3,(2pi)/3$

Related questions

Impact of this question

898 views around the world

You can reuse this answer
Creative Commons License