How to do this?

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1 Answer
Øko
Apr 24, 2018

#theta=pi/3,(2pi)/3#

Explanation:

We want to solve the equation

#2sin(theta)-sqrt(3)=0#

Solve for #sin(theta)#

#2sin(theta)=sqrt(3)#

#=>sin(theta)=sqrt(3)/2#

And here the angles should be remembered as

#theta=pi/3,(2pi)/3#

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