Joan left Durham traveling 85 mph. Mike,to catch up,left some time later driving at 94 mph. Mike caught up after 7 hours. How long was Joan driving before Mike caught up?

1 Answer
Apr 26, 2018

Joan had been driving for 7hours 44mins

Explanation:

*Before we start we should immediately note that speed, distance and time are all present in the question. Therefore we know we will most likely need to use the equation: Speed=DistanceTime

Firstly let's call the place where the two people meet x.

To get to point x Joan travelled at 85mph for y amount of time.

To get to point x Mike travelled at 94mph for 7 hours.

Mike has given us both speed and time We can, therefore, now work out the distance Mike meets Joan.
-Rearrange the formula :Distance=Speed×Time

Distance=94×7

Distance=658miles

We now know that the point they both meet at (which we called x to start with is: 658

We now know the Distance and Speed of Joan. We can, therefore, work out the length of time Joan has been travelling.
-Rearrange the formula: Time=DistanceSpeed
Time=65885

Time=7.74hours(2.D.P.)

Now all that remains for us to do is work out how many minutes Joan has been travelling for.

mins60×100=74

mins60=74100

mins=74100×60

mins=44

Joan has therefore been travelling for 7hours 44mins