Question

How do you solve `5+ x + 7x = - 3`?

Answer 1

See a solution process below:

Explanation:

First, combine like terms on the left side of the equation:

`5 + x + 7x = -3`

`5 + 1x + 7x = -3`

`5 + (1 + 7)x = -3`

`5 + 8x = -3`

Next, subtract `color(red)(5)` from each side of the equation to isolate the `x` term while keeping the equation balanced:

`5 - color(red)(5) + 8x = -3 - color(red)(5)`

`0 + 8x = -8`

`8x = -8`

Now, divide each side of the equation by `color(red)(8)` to solve for `x` while keeping the equation balanced:

`(8x)/color(red)(8) = -8/color(red)(8)`

`(color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8)) = -1`

`x = -1`

Answer 2

`x = -1`

Explanation:

Transposing the terms and adding like terms gives us,

`x + 7x =-3-5`

`8x=-8`

`x = -1`

Answer 3

`x=-1`

Explanation:

`"collect terms in x on the left side of the equation and"`
`"numeric values on the right side"`

`rArr5+8x=-3`

`"subtract "5" from both sides"`

`cancel(5)cancel(-5)+8x=-3-5`

`rArr8x=-8`

`"divide both sides by "8`

`(cancel(8) x)/cancel(8)=(-8)/8`

`rArrx=-1`

`color(blue)"As a check"`

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

`5-1-7=-3=" right side"`

`rArrx=-1" is the solution"`