Int(x-1)(x-2)/x+4 dx ?

1 Answer
Øko
Apr 28, 2018

I=1/2x^2-7x+30ln(abs(x+4))+C

Explanation:

I assume you meant

I=int((x-1)(x-2))/(x+4)dx

color(white)(I)=int(x^2-3x+2)/(x+4)dx

By long division

I=intx-7+30 1/(x+4)dx

color(white)(I)=intxdx-int7dx+30int1/(x+4)dx

color(white)(I)=1/2x^2-7x+30ln(abs(x+4))+C

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