Int(x-1)(x-2)/x+4 dx ?
1 Answer
Apr 28, 2018
Explanation:
I assume you meant
I=int((x-1)(x-2))/(x+4)dxI=∫(x−1)(x−2)x+4dx
color(white)(I)=int(x^2-3x+2)/(x+4)dxI=∫x2−3x+2x+4dx
By long division
I=intx-7+30 1/(x+4)dxI=∫x−7+301x+4dx
color(white)(I)=intxdx-int7dx+30int1/(x+4)dxI=∫xdx−∫7dx+30∫1x+4dx
color(white)(I)=1/2x^2-7x+30ln(abs(x+4))+CI=12x2−7x+30ln(|x+4|)+C