The perimeter of a parking lot is 500 yards. The length is 50 yards more than three times the width.Find the dimensions?

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Answer 1 · 2018-04-30T00:25:24

$w = 50$ $w=50$ yards

$l = 200$ $l=200$ yards

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The perimeter is:

$P = 2 l + 2 w$ $P=2l+2w$ where $l$ $l$ is the length and $w$ $w$ is the width.

$l = 3 w + 50$ $l=3w+50$ yards

$P = 2 (3 w + 50) + 2 w = 500$ $P=2(3w+50)+2w=500$ yards

$6 w + 100 + 2 w = 500$ $6w+100+2w=500$

$8 w = 400$ $8w=400$

$w = 50$ $w=50$ yards

$l = 3 (50) + 50 = 200$ $l=3(50)+50=200$ yards