X^2+20x-69?

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X^2+20x-69?

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Answer 1 · 2018-05-01T05:51:03

$x^{2} + 20 x - 69 = (x + 23) (x - 3)$ $x^2 + 20x -69 = (x + 23)(x - 3)$
$\Rightarrow x = - 23 or x = 3$ $implies x = -23 or x = 3$

Explanation:

$x^{2} + 20 x - 69 = 0$ $x^2 + 20x -69 = 0$
$\Rightarrow x^{2} + 23 x - 3 x - 69$ $implies x^2 + 23x - 3x - 69$
Factoring out x and -3 respectively,
$\Rightarrow x (x + 23) - 3 (x + 23) = 0$ $impliesx(x + 23) -3(x+23) = 0$
Factoring out (x + 23)
$\Rightarrow (x + 23) (x - 3) = 0$ $implies (x+23)(x-3) = 0$
Using the zero product rule,
$x + 23 = 0 or x - 3 = 0$ $x + 23 = 0 or x - 3 = 0$
$\Rightarrow x = - 23 or x = 3$ $implies x = -23 or x = 3$

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X^2+20x-69?

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